A) \[\sqrt{\left( \frac{2g}{h} \right)}\]
B) \[\sqrt{\left( \frac{2u}{g} \right)}\]
C) \[\sqrt{\left( \frac{h}{2g} \right)}\]
D) \[\sqrt{\left( \frac{2h}{g} \right)}\]
Correct Answer: D
Solution :
The initial velocity of aeroplane is horizontal, then the vertical component of velocity of packet will be zero. So \[t=\sqrt{\frac{2h}{g}}\]
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