A) 2 sec
B) 3 sec
C) 4 sec
D) None of these
Correct Answer: C
Solution :
Total distance \[=\frac{1}{2}g{{t}^{2}}=\frac{25}{2}g\] Distance moved in 3 sec \[=\frac{9}{2}g\] Remaining distance \[=\frac{16}{2}g\] If t is the time taken by the stone to reach the ground for the remaining distance then \[\Rightarrow \frac{16}{2}g=\frac{1}{2}g{{t}^{2}}\Rightarrow t=4\ \sec \]
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