JEE Main & Advanced Physics Motion in a Straight Line / सरल रेखा में गति Question Bank Motion Under Gravity

  • question_answer
    A mass m slips along the wall of a semispherical surface of radius R. The velocity at the bottom of the surface is              [MP PMT 1993]                    

    A)             \[\sqrt{Rg}\]

    B)             \[\sqrt{2Rg}\]

    C)             \[2\sqrt{\pi Rg}\]

    D)             \[\sqrt{\pi Rg}\]

    Correct Answer: B

    Solution :

                    By applying law of conservation of energy             \[mgR=\frac{1}{2}m{{v}^{2}}\Rightarrow v=\sqrt{2Rg}\]


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