A) At \[h/2\]from the ground
B) At \[h/4\] from the ground
C) Depends upon mass and volume of the body
D) At \[3h/4\] from the ground
Correct Answer: D
Solution :
Let the body after time \[t/2\]be at x from the top, then \[x=\frac{1}{2}g\frac{{{t}^{2}}}{4}=\frac{g{{t}^{2}}}{8}\] ?(i) \[h=\frac{1}{2}g{{t}^{2}}\] ?(ii) Eliminate t from (i) and (ii), we get \[x=\frac{h}{4}\] \[\therefore \] Height of the body from the ground \[=h-\frac{h}{4}=\frac{3h}{4}\]
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