question_answer

Figure shows the graph of the x-coordinate of a particle going along the X-axis as a function of time. What is (a) the average velocity during 0 to 10s. (b) instantaneous velocity at 5, 12s.

Answer:

  (a) \[Average\,velocity=\frac{total\,\,displacement}{time}\] from the given graph Average velocity \[=\frac{100}{10}=10m/s\] (b) Instantaneous velocity at any time is equal to the slope of that line at \[A=\frac{50}{2.5}=20m/s\] at 5 sec instantaneous velocity = zero. Since slope along AB is zero. at 12 sec, = slope\[=\frac{0-100}{5a}=-20m/s\]