question_answer

An object having a velocity 4.0 m/s is accelerated at the rate of\[\text{1}.\text{2m}/{{\text{s}}^{\text{2}}}\]for 5.0s. Find the distance travelled during the period of acceleration.

Answer:

Given velocity, \[v=4.0\,m/s\] Acceleration \[a=1.2m/{{s}^{2}}\] time, t = 5.0 seconds we know, distance travelled \[a=ut+\frac{1}{2}a{{t}^{2}}=4.0\times 5.0=\frac{1}{2}\times 1.2{{(5.0)}^{2}}\] \[=20.0+25.0\times 0.6=20.0+15.0=35.0m\]