question_answer

Moving with uniform acceleration, a body covers 150 m during 10 sec so that it covers 24 m during the tenth second. Find the initial velocity and acceleration of the body.

Answer:

From\[S=ut+\frac{1}{2}a{{t}^{2}}\] \[\Rightarrow 150=10u+\frac{1}{2}a{{(10)}^{2}}\] \[\Rightarrow 150=10u+50a\]                                     …..(1) From \[{{S}_{n}}=u+\frac{a}{2}(2n-1)\] \[\Rightarrow 24=u+\frac{a}{2}(2\times 10-1)\] \[\Rightarrow 48=2u+19a\]                                         …..(2) On solving equations (1) and (2) \[u=5\,m{{s}^{-1}}\]and\[a=2\,m{{s}^{-2}}\]