JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Motion on Inclined Surface

  • question_answer
    A block is at rest on an inclined plane making an angle \[\alpha \] with the horizontal. As the angle \[\alpha \] of the incline is increased, the block starts slipping when the angle of inclination becomes \[\theta \]. The coefficient  of static friction between the block and the surface of the inclined plane is or             A body starts sliding down at an angle \[\theta \] to horizontal. Then coefficient of friction is equal to            [CBSE PMT 1993]            

    A)                         \[\sin \theta \]              

    B)                         \[\cos \theta \]            

    C)                         \[\tan \theta \]            

    D)                         Independent of \[\theta \]

    Correct Answer: C

    Solution :

                                Coefficient of friction = Tangent  of angle of repose             \[\therefore \] \[\mu =\tan \theta \]            


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