A) \[\frac{3}{4}\tan \theta \]
B) \[\frac{2}{3}\tan \theta \]
C) \[\frac{1}{4}\tan \theta \]
D) \[\frac{1}{2}\tan \theta \]
Correct Answer: A
Solution :
\[\mu =\tan \theta \left( 1-\frac{1}{{{n}^{2}}} \right)\]\[=\tan \theta \left( 1-\frac{1}{{{2}^{2}}} \right)=\frac{3}{4}\tan \theta \]
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