JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Motion on Inclined Surface

  • question_answer
    A 2 kg mass starts from rest on an inclined smooth surface with inclination 30o and length 2 m.  How much will it travel before coming to rest on a frictional surface with frictional coefficient of 0.25                           [UPSEAT 2003]

    A)             4 m     

    B)             6 m

    C)             8 m     

    D)             2 m

    Correct Answer: A

    Solution :

                             \[{{v}^{2}}={{u}^{2}}+2as=0+2\times g\sin 30\]\[\times 2\] Þ \[v=\sqrt{20}\]             Let it travel distance ?S? before coming to rest             \[S=\frac{{{v}^{2}}}{2\mu g}=\frac{20}{2\times 0.25\times 10}=4m\]


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