JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Motion on Inclined Surface

  • question_answer
    A block of mass 10 kg is placed on an inclined plane.  When the angle of inclination is 30o, the block just begins to slide down the plane.  The force of static friction is                                     [Kerala (Engg.) 2001]

    A)             10 kg wt

    B)               89 kg wt

    C)             49 kg wt

    D)               5 kg wt

    Correct Answer: D

    Solution :

                    \[F=mg\sin 30{}^\circ =50N=5kg\text{-}wt\].


You need to login to perform this action.
You will be redirected in 3 sec spinner