A) 1 cm
B) 2 cm
C) 3 cm
D) 4 cm
Correct Answer: A
Solution :
Case (i) | Case (ii) |
\[{{u}_{1}}=u\] | \[{{u}_{2}}=u-2\] |
\[{{v}_{1}}=\frac{u}{2}\] | \[=\frac{u}{2}\] |
\[{{a}_{1}}=-a\] | \[{{a}_{2}}=-a\] |
\[{{S}_{1}}=3\,cm\] | \[{{S}_{2}}=?\] |
\[\frac{{{u}^{2}}}{4}-{{u}^{2}}\] | \[{{O}_{2}}-\frac{{{u}^{2}}}{4}=2\times (-a)\times {{S}_{2}}\] |
\[=2\times (-a)\times 3\] | |
\[-\frac{3}{4}{{u}^{2}}=-6a\] | \[-\frac{{{u}^{2}}}{4}=-2a{{s}_{2}}\] |
\[\frac{3{{u}^{2}}}{4}=6a\]……(1) | \[\frac{{{u}^{2}}}{4}=2a{{s}_{2}}\]…..(2) |
\[\frac{\frac{{{u}^{2}}}{4}}{\frac{3{{u}^{2}}}{4}}=\frac{2a{{s}_{2}}}{6a}\] | \[\frac{1}{3}=\frac{1}{3}{{S}_{2}}\] |
\[{{S}_{2}}=1\,cm\] |
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