List - A | List - B |
(i) Velocity along AB | (a)\[\text{1}.\text{25 m}{{\text{s}}^{-\text{1}}}\] |
(ii) Velocity along DE | (b) Zero |
(iii) Average velocity along CE | (c)\[-\text{7}.\text{5 m}{{\text{s}}^{-\text{1}}}\] |
(d)\[\text{2}.\text{1m}{{\text{s}}^{-\text{1}}}\] |
Answer:
(i) Velocity between ‘0’ to 2s
\[=\frac{10-25}{2}=\frac{-15}{2}=-7.5m/s\]
(ii) Velocity between ‘8s’ to 12s
\[=\frac{final\,\,velocity\,\,initial\,\,velocity}{Total\,\,time\,\,taken}\]
\[=\frac{25-20}{12-8}=\frac{5}{4}=1.25m/s\]
(iii) Average velocity between 5s to 12s
\[=\frac{displacement\,\,\operatorname{cov}ered}{Total\,time\,\,taken}=\frac{25-10}{12-5}\]
\[=\frac{15}{7}=2.1m/s\]
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