question_answer

Acceleration-time graph of a particle moving in a straight line is shown in figure. Velocity of particle at time t = 0 is 2 m/s. Find the velocity at the end of fourth second.

Answer:

Change in velocity = area under a-t graph Hence \[{{V}_{final}}-{{V}_{initial}}=\frac{1}{2}(4)(4)=8m/s\] \[{{V}_{final}}={{V}_{initial}}+8=(2+8)m/s=10m/s\]