|
Answer:
(i) A to B
\[{{x}_{1}}=0\] \[{{t}_{1}}=0\]
\[{{x}_{2}}=3\] \[{{t}_{2}}=5\]
\[\therefore v=\frac{{{x}_{2}}-{{x}_{1}}}{{{t}_{2}}-{{t}_{1}}}=\frac{3-0}{5-0}=\frac{3}{5}cm/s\]
(ii) B to C
As there is no change in the position, the speed is zero
(iii) CD
\[v=\alpha \] \[{{t}_{1}}\]
\[{{t}_{1}}=\frac{v}{\alpha }\] \[{{t}_{2}}\]
\[\therefore v=\frac{7-3}{9-7}=\frac{4}{2}cm/s\]
You need to login to perform this action.
You will be redirected in
3 sec
