Answer:
\[V_{2}^{2}-V_{1}^{2}=-2ax\] ………….(1)
\[V_{3}^{2}-V_{2}^{2}=-2ax\] …………. (2)
equating (1) & (2), we get\[{{V}_{2}}=\sqrt{\frac{V_{2}^{2}+V_{3}^{2}}{2}}\]
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