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JEE Main & Advanced Chemistry States of Matter / पदार्थ की अवस्थाएँ - गैस एवं द्रव Question Bank Molecular speeds

  • question_answer
    The average kinetic energy of an ideal gas per molecule in SI units at \[{{25}^{o}}C\] will be          [CBSE PMT 1996]

    A)                 \[6.17\times {{10}^{-21}}\,kJ\]  

    B)                 \[6.17\times {{10}^{-21}}\,J\]

    C)                 \[6.17\times {{10}^{-20}}\,J\]    

    D)                 \[6.17\times {{10}^{-20}}\,J\]

    Correct Answer: B

    Solution :

               Average kinetic energy per molecule                                 \[=\frac{3}{2}KT=\frac{3}{2}\times 1.38\times {{10}^{-23}}\times 300J\] =\[6.17\times {{10}^{-21}}J\]


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