A) 150 K
B) 600 K
C) 900 K
D) 1200 K
Correct Answer: D
Solution :
\[\frac{{{U}_{S{{O}_{2}}}}}{{{U}_{He}}}=\frac{1}{2}=\sqrt{\frac{{{M}_{He}}}{{{M}_{S{{O}_{2}}}}}\frac{{{T}_{S{{O}_{2}}}}}{{{T}_{He}}}}=\sqrt{\frac{4}{64}.\frac{{{T}_{S{{O}_{2}}}}}{300}}\] \[=\frac{4}{64}\frac{{{T}_{S{{O}_{2}}}}}{300}=\frac{1}{4}\]; \[{{T}_{S{{O}_{2}}}}={{1200}^{o}}K\]You need to login to perform this action.
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