A) 10.33 atm
B) 9.33 atm
C) 9.74 atm
D) 9.2 atm
Correct Answer: B
Solution :
\[\left( P-\frac{{{n}^{2}}a}{{{V}^{2}}} \right)\left( V-nb \right)=nRT\] \[\left( P-\frac{{{(2)}^{2}}\times 4.17}{{{(5)}^{2}}} \right)\left( 5-2\times .03711 \right)=2\times .0821\times 300\] \[P=\frac{2\times .0821\times 300}{5-2\times .03711}-\frac{4.7\times {{2}^{2}}}{{{5}^{2}}}\Rightarrow 10-0.66\]\[=9.33atm\]
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