A) \[1200K\]
B) \[900\,K\]
C) \[600K\]
D) \[150K\]
Correct Answer: A
Solution :
\[{{V}_{rms}}=\sqrt{\frac{3RT}{M}}\]Þ \[{{V}_{rms}}=\sqrt{T}\] Given \[{{V}_{1}}=V\], \[{{T}_{1}}=300K\], \[{{V}_{2}}=2V\], \[{{T}_{2}}=?\] \[\frac{{{V}_{1}}}{{{V}_{2}}}=\sqrt{\frac{{{T}_{1}}}{{{T}_{2}}}}\]; \[{{\left( \frac{V}{2V} \right)}^{2}}=\frac{300}{{{T}_{2}}}\] Þ \[{{T}_{2}}=300\times 4=1200K\]
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