A) \[N_{2}^{+}\]
B) \[C{{N}^{-}}\]
C) \[CO\]
D) \[N{{O}^{+}}\]
Correct Answer: A
Solution :
\[O_{2}^{+}(15{{e}^{-}})=K:{{K}^{*}}{{(\sigma 2s)}^{2}}{{({{\sigma }^{*}}2s)}^{2}}{{(\sigma 2{{p}_{x}})}^{2}}\] \[{{(\pi 2{{p}_{y}})}^{2}}{{(\pi 2{{p}_{z}})}^{2}}{{({{\pi }^{*}}2{{p}_{y}})}^{1}}{{({{\pi }^{*}}2{{p}_{z}})}^{0}}\] Hence, bond order \[=\frac{1}{2}(10-5)=2.5\] \[N_{2}^{+}(13{{e}^{-}})=K{{K}^{*}}{{(\sigma 2s)}^{2}}{{({{\sigma }^{*}}2s)}^{2}}{{(\sigma 2{{p}_{x}})}^{2}}\] \[{{(\pi \,2{{p}_{y}})}^{2}}{{(\pi \,2{{p}_{z}})}^{1}}\] Hence, bond order \[=\frac{1}{2}(9-4)=2.5\].
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