JEE Main & Advanced Physics Wave Mechanics Question Bank Mock Test - Waves and Acoustics

  • question_answer
    A tuning fork of known frequency 256 Hz makes 5 beats per second with the vibrating string of a piano. The beat frequency decreases to 2 beats per second when the tension in the piano string is slightly increased. The frequency of the piano string before increasing the tension was

    A) 256 + 5 Hz       

    B) 256 + 2 Hz

    C) 256 - 2 Hz        

    D) 256 - 5 Hz

    Correct Answer: D

    Solution :

    [d] Suppose \[{{n}_{p}}\] = frequency of piano =? \[({{n}_{p}}\propto \sqrt{T})\] \[{{n}_{f}}\]= Frequency of tuning fork = 256 Hz x = Beat frequency = 5 bps, which is decreasing \[(5\to 2)\] after changing the tension of piano Wire Also, tension of piano wire is increasing so \[{{n}_{p}}\downarrow \] Hence \[{{n}_{p}}\uparrow -{{n}_{f}}=x\downarrow \to \] Wrong \[{{n}_{f}}-{{n}_{p}}\uparrow =x\downarrow \to \] Correct \[\Rightarrow {{n}_{p}}={{n}_{f}}-x=256-5Hz.\]


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