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JEE Main & Advanced Physics Wave Mechanics Question Bank Mock Test - Waves and Acoustics

  • question_answer
    The linear density of a vibrating string is\[{{10}^{-4}}kg/m\]. A transverse wave is propagating on the string, which is described by the equation\[y=0.02\sin (x+30t)\], where \[x\] and\[y\] are in metres and time \[t\] in seconds. Then tension in the string is

    A) 0.09 N  

    B) 0.36 N

    C) 0.9 N   

    D) 3.6 N

    Correct Answer: A

    Solution :

    [a] \[y=0.02\sin \,(x+30t)\] Comparing with standard equation \[y=A\sin (kx+\omega t),\,\,\omega =30,\,\,k=1\] Velocity of wave, \[v=\frac{\omega }{k}=\frac{30}{1}=30m/s\] Expression \[v=\sqrt{\frac{T}{m}}\]gives Tension \[T={{v}^{2}}n={{(30)}^{2}}\times {{10}^{-4}}=0.09\] N 


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