A) \[{{T}_{2}}\] was decreased
B) \[{{T}_{2}}\]was increased
C) \[{{T}_{1}}\] was increased
D) \[{{T}_{1}}\]was kept constant
Correct Answer: B
Solution :
[b] Using \[n=\frac{1}{2l}\sqrt{\frac{T}{m}};\] As \[{{T}_{1}}>{{T}_{2}}\Rightarrow {{n}_{1}}>{{n}_{2}}\]giving \[{{n}_{1}}-{{n}_{2}}=6\] The beat frequency of 6 will remain fixed when (i) \[{{n}_{1}}\] remains same but \[{{n}_{2}}\] is increased to a new value \[(n{{'}_{2}}-{{n}_{2}}=12)\] increasing tension \[{{T}_{2}}\]. (ii) \[{{n}_{2}}\] remains same but \[{{n}_{1}}\] is decreased to a new value \[({{n}_{1}}-n{{'}_{1}}=12)\] by decreasing tension \[{{T}_{1}}\].
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