A) \[I=\sqrt{{{A}^{2}}+{{B}^{2}}{{\cos }^{2}}\varphi }\]
B) \[I=\frac{A}{B}\cos \varphi \]
C) \[I=A+B\cos \frac{\varphi }{2}\]
D) \[I=A+B\cos \]
Correct Answer: D
Solution :
[d] \[I={{a}_{1}}^{2}+{{a}_{2}}^{2}+2{{a}_{1}}{{a}_{2}}\cos \varphi \] Put \[{{a}_{1}}^{2}+{{a}_{2}}^{2}=A\] and \[{{a}_{1}}{{a}_{2}}=B\] \[\therefore I=A+B\cos \varphi \]
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