question_answer

Assuming human pupil to have a radius of 0.25 cm and a comfortable viewing distance of 25 cm, the minimum separation between two objects that human eye can resolve at 500 nm wavelength is

A) \[1\mu m\]        

B) \[30\mu m\]

C) \[100\mu m\]     

D) \[300\mu m\]

Correct Answer: B

Solution :

[b] \[RP=\frac{1.22\lambda }{2\mu \sin \theta }=\frac{1.22\times (500\times {{10}^{-9}}m)}{2\times 1\times \left( \frac{1}{100} \right)}\] Or \[RP=3.05\times {{10}^{-5}}m=30\mu m\]