A) \[2\lambda \]
B) \[2\lambda /3\]
C) \[\lambda /3\]
D) \[\lambda \]
Correct Answer: A
Solution :
[a] Path difference due to slab should be integral multiple of\[\lambda \]. Hence, \[\Delta x=n\lambda \] Or \[(\mu -1)t=n\lambda ,\] \[n=1,2,...\] Or \[t=\frac{n\lambda }{\mu -1}\] For minimum value of t, n=1. \[\therefore t=\frac{n\lambda }{\mu -1}=\frac{\lambda }{1.5-1}=2\lambda \]
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