A) \[n\pi -\frac{\pi }{6},n\in z\]
B) \[2n\pi \pm \frac{11\pi }{6},n\in z\]
C) \[n\pi \pm \frac{\pi }{6},n\in z\]
D) \[2n\pi +\frac{11\pi }{6},n\in z\]
Correct Answer: D
Solution :
[d] \[\sqrt{3}\tan \theta +1=0\] and \[\sqrt{3}\sec \theta -2=0\] \[\Rightarrow \theta =\frac{11\pi }{6}\] \[\Rightarrow \theta =2n\pi \pm \frac{11\pi }{6},n\in Z\]
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