A) \[N{{a}_{2}}{{O}_{2}}\] and \[N{{a}_{2}}C{{O}_{3}}\]
B) \[N{{a}_{2}}O\] and \[N{{a}_{2}}C{{O}_{3}}\]
C) \[N{{a}_{2}}{{O}_{2}}\] and \[NaAl{{O}_{2}}\]
D) \[NaAl{{O}_{2}}\] and \[N{{a}_{2}}C{{O}_{3}}\]
Correct Answer: B
Solution :
| [b] \[A{{l}_{2}}{{O}_{3}}+6Na\to 3N{{a}_{2}}O(X)+2Al;\] |
| \[N{{a}_{2}}O+{{H}_{2}}O\to 2NaOH\] |
| \[NaOH+C{{O}_{2}}\to N{{a}_{2}}C{{O}_{3}}+{{H}_{2}}O\] |
| Note: \[N{{a}_{2}}{{O}_{2}}\] is formed in presence of air. |
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