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JEE Main & Advanced Chemistry Surface & Nuclear Chemistry / भूतल और नाभिकीय रसायन Question Bank Mock Test - Surface Chemistry

  • question_answer
    In the Freundlich adsorption isotherm, \[\log \left( \frac{x}{m} \right)=\log k+\frac{1}{n}\log p\], the value of n is

    A) any value from 0 to 1

    B) a positive integer

    C) a negative integer

    D) a positive or a negative fractional number

    Correct Answer: B

    Solution :

    [b] When\[\frac{1}{n}=0\], \[\log \left( \frac{x}{m} \right)=\log \,k,\left( \frac{x}{m} \right)\propto k\] When \[\frac{1}{n}=1.\] \[\log \left( \frac{x}{m} \right)=\log k+\log P\] \[\left( \frac{x}{m} \right)=k(p)\] Thus, n is a positive integer.


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