question_answer

A straight line through the point A.(3, 4) is such that its intercept between the axes is bisected at A. its equation is

A) \[x+y=7\]        

B) \[3x-4y+7=0\]

C) \[4x+3y=24\]   

D) \[3x+4y=25\]

Correct Answer: C

Solution :

[c] Since P is mid-Point of the line, intercept on axes are 6 and 8. \[\therefore \] Equation of line is \[\frac{x}{6}+\frac{y}{8}=1\] Or \[4x+3y=24\]