A) \[a=64/115,\text{ }b=112/15\]
B) \[a=14/15,\text{ }b=-8/115\]
C) \[a=64/115,\text{ }b=-8/115\]
D) \[a=64/15,\text{ }b=14/15\]
Correct Answer: C
Solution :
[c] \[ax+by=1\]Will be one of the bisectors of the given line. Equations of bisectors of the given lines are \[\frac{3x+4y-5}{5}=\pm \left( \frac{5x-12y-10}{13} \right)\] Or \[64x-8y=115\] Or \[14x+112y=15\] Or \[a=\frac{64}{115},b=-\frac{8}{115}\] Or \[a=\frac{14}{15},b=\frac{12}{115}\]
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