A) 2
B) 2.57
C) 3
D) 3.75
Correct Answer: B
Solution :
[b] Given, observations are 3, 10, 10, 4, 7, 10 and 5. \[\therefore \bar{x}=\frac{3+10+10+4+7+10+5}{7}=\frac{49}{7}=7\]\[{{x}_{i}}\] | \[{{d}_{i}}=\left| {{x}_{i}}-\bar{x} \right|\] |
3 | 4 |
10 | 3 |
10 | 3 |
4 | 3 |
7 | 0 |
10 | 3 |
5 | 3 |
Total | \[\Sigma \,{{d}_{i}}=18\] |
You need to login to perform this action.
You will be redirected in
3 sec