JEE Main & Advanced Mathematics Statistics Question Bank Mock Test - Statistics

  • question_answer
    The mean of 100 observations is 50 and their standard deviation is 5. The sum of squares of all the observations is

    A) 50000  

    B) 250000

    C) 252500 

    D) 255000

    Correct Answer: C

    Solution :

    [c] Given, \[\bar{x}=50,n=100\]and \[\Sigma =5\] \[\Sigma \,50=\frac{\Sigma \,{{x}_{i}}}{100}\] \[\Rightarrow \Sigma \,{{x}_{i}}=50\times 100=5000\] Now, \[{{\Sigma }^{2}}=\frac{\Sigma \,x_{i}^{2}}{n}-{{(\bar{x})}^{2}}\] \[\Rightarrow 25=\frac{\Sigma \,x_{i}^{2}}{100}-{{(50)}^{2}}\] \[\Rightarrow 2525=\frac{\Sigma \,x_{i}^{2}}{100}\] \[\therefore \,\,\,\Sigma \,{{x}_{i}}^{2}=252500\]


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