A) 5.5
B) 3.87
C) 2.97
D) 2.87
Correct Answer: D
Solution :
[d] we know that, SD of first n natural numbers\[=\sqrt{\frac{{{n}^{2}}-1}{12}}\] \[\therefore \]SD of first 10 natural numbers \[=\sqrt{\frac{{{10}^{2}}-1}{12}}\] \[=\sqrt{\frac{100-1}{12}}=\sqrt{\frac{99}{12}}=\sqrt{8.25}=2.87\]
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