A) 63.5 g
B) 31.75 g
C) 34 g
D) 2 g
Correct Answer: C
Solution :
\[C{{u}^{2+}}+{{H}_{2}}S\to C{{u}_{2}}S+{{H}_{2}}\] 63.5g 1 mole of \[C{{u}^{2+}}\]requires 1 mole of \[{{H}_{2}}S\] Or 63.5 g of \[C{{u}^{2+}}\]requires 34 g of \[{{H}_{2}}S\] [Molar mass of \[{{H}_{2}}S\]=2+32=34g] So 1 mole \[{{H}_{2}}S\]is required, i.e, 34 gYou need to login to perform this action.
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