A) 25%
B) 75%
C) 46%
D) 54%
Correct Answer: C
Solution :
\[{{\chi }_{2}}=\frac{{{n}_{2}}}{{{n}_{1}}+{{n}_{2}}}=0.25\](ethanol) (solute) \[(M{{w}_{2}}=46g)\] \[{{\chi }_{1}}=\frac{{{n}_{1}}}{{{n}_{1}}+{{n}_{2}}}=0.75\](water) (solvent) \[(M{{w}_{1}}=18g)\] \[\frac{{{\chi }_{1}}}{{{\chi }_{2}}}=\frac{{{n}_{1}}}{{{n}_{2}}}=\frac{3}{1}\Rightarrow \frac{{{W}_{1}}\times M{{w}_{2}}}{M{{w}_{1}}\times {{W}_{2}}}=\frac{3}{1}\] \[\frac{{{W}_{1}}\times 46}{18\times {{W}_{2}}}=3\] \[\frac{{{W}_{1}}}{{{W}_{2}}}=1.17\] \[\therefore \] \[\frac{{{W}_{2}}}{{{W}_{1}}+{{W}_{2}}}=0.46\]
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