A) 34.2 g
B) 72 g
C) 342 g
D) 460 g
Correct Answer: B
Solution :
[b] \[{{T}_{b}}-{{T}_{f}}=105=100+5\] \[{{T}_{b}}-{{T}_{b}}^{0}-{{T}_{f}}=5\] \[[\because {{T}_{b}}^{o}=100{}^\circ C]\] \[\Delta {{T}_{b}}-{{T}_{f}}+{{T}_{f}}^{o}-{{T}_{f}}^{o}=5\] \[\Rightarrow \Delta {{T}_{b}}+\Delta {{T}_{f}}=5\] \[[\because {{T}_{f}}^{o}=0{}^\circ C]\] \[\Delta {{T}_{f}}+\Delta {{T}_{b}}=m({{k}_{f}}+{{k}_{b}})\] \[\Delta {{T}_{f}}+\Delta {{T}_{b}}=5=\frac{x}{\frac{342}{\frac{100}{1000}}}(1.86+0.51)\] \[5=\frac{10x}{342}\times 2.37\Rightarrow x=72\,g\]
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