JEE Main & Advanced Chemistry Solutions / विलयन Question Bank Mock Test - Solutions

  • question_answer
    The vapour pressure of n-hexane at 350 K is 840 torr and that of cyclohexane is 600 torr. Mote fraction of hexane in the mixture that boils at 350 K and 1 atm pressure assuming ideal behaviour is

    A) 0.67                 

    B) 0.80

    C) 0.50                 

    D) 2.2

    Correct Answer: A

    Solution :

    [a] Mixture boils at 1 atm and 350 K Thus, total vapour pressure is 1 atm =760 torr (h) used for hexane and (ch) for cyclohexane. \[{{p}_{total}}={{p}_{h}}^{0}{{\chi }_{h}}^{0}+{{p}_{ch}}^{0}{{\chi }_{ch}}\Rightarrow {{p}_{total}}\] \[={{p}_{h}}^{0}{{\chi }_{h}}+{{p}_{ch}}^{0}(1-{{\chi }_{h}})\] \[760=840{{\chi }_{h}}+600(1-{{\chi }_{h}})\] \[\therefore {{\chi }_{h}}=0.67\]


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