JEE Main & Advanced Chemistry Solutions / विलयन Question Bank Mock Test - Solutions

  • question_answer
    What mass of non-volatile solute (urea) needs to be dissolved in 150 g of water in order to decrease the vapour pressure of water by 35%. What will be the molality of solution?

    A) 23.88   

    B) 31.12

    C) 25.47   

    D) 29.92

    Correct Answer: D

    Solution :

    [d] Using Raoult's Law: \[\frac{{{P}^{0}}-{{P}_{S}}}{{{P}_{S}}}=\frac{{{W}_{2}}M{{w}_{1}}}{M{{w}_{2}}.{{W}_{1}}}\] If \[{{P}^{0}}=100mm\] then \[{{P}_{S}}=100-35=65\,mm\] \[\frac{100-65}{65}=\frac{{{W}_{2}}\times 18}{60\times 18}\] \[\Rightarrow {{W}_{2}}=\frac{35\times 60\times 150}{65\times 18}=269.23\] \[\therefore \]Molality \[=\frac{{{W}_{2}}\times 1000}{M{{w}_{2}}\times {{W}_{1}}}=\frac{269.23\times 1000}{60\times 150}\] \[=29.92m\]


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