A) \[\alpha =\frac{i-1}{(x+y-1)}\]
B) \[\alpha =\frac{i-1}{x+y+1}\]
C) \[\alpha =\frac{x+y-1}{i-1}\]
D) \[\alpha =\frac{x+y+1}{i-1}\]
Correct Answer: A
Solution :
[a] van?t Hoff factor (i) is related degree of dissociation (\[\alpha \]) as \[\alpha =\frac{i-1}{n-1}\] Here, n are the moles of an electrolyte \[\left( A-B \right)\] dissolve in a solvent. For \[{{A}_{x}}{{B}_{y}},{{A}_{x}}{{B}_{y}}\rightleftharpoons x{{A}^{+y}}+y{{B}^{-x}}\] Therefore, \[\alpha =\frac{i-1}{(x+y-1)}\]
You need to login to perform this action.
You will be redirected in
3 sec
