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JEE Main & Advanced Chemistry Solutions / विलयन Question Bank Mock Test - Solutions

  • question_answer
    Molar solubility of helium, nitrogen and oxygen are plotted against partial pressure of the gas at constant temperature. Henry's law constant for hese gases will lie in the following sequence?

    A) \[{{O}_{2}}>{{N}_{2}}>He\]

    B) \[{{O}_{2}}<{{N}_{2}}<He\]

    C) \[{{O}_{2}}={{N}_{2}}=He\]

    D) \[{{O}_{2}}>{{N}_{2}}>He\]

    Correct Answer: B

    Solution :

    [b]
    Gas Temperature \[{{K}_{H}}\](K bar)
    \[He\] 293 144.97
    \[{{N}_{2}}\] 293 76.48
    \[{{O}_{2}}\] 293 34.86
    The higher the value of Henry?s law constant, the lower is the solubility of the gas in the liquid.


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