A) 0
B) 1
C) 2
D) more then 2
Correct Answer: B
Solution :
[b] Given \[f(x+y)=f(x)+f(y)-xy-1\forall x,y\in R\] \[f(1)=1\] \[f(2)=f(1+1)=f(1)+f(1)-1-1=0\]\[f(3)=f(2+1)=f(2)+f(1)-2\times 1-1=-2\] |
\[f(n+1)=f(n)+f(1)-n-1=f(n)-n<f(n)\] |
\[Thus,\text{ }f(1)>f(2)>f(3)>....,\,\,and\text{ }f(1)=1.\] |
\[Therefore,\text{ }f(1)=1\,\,and\,\,f(n)<1,for\text{ }n>1\] |
\[Hence,\text{ }f(n)=n,n\in N,hasonlyonesolution\text{ }n=1.\] |
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