A) 0.010 mole of oxygen is liberated
B) 0.005 mole of \[KMn{{O}_{4}}\]are left
C) 0.030 g atom of oxygen is evolved.
D) 0.0025 mole \[{{H}_{2}}{{O}_{2}}\]does not react with \[KMn{{O}_{4}}\]
Correct Answer: B
Solution :
[b] M eq. of \[KMn{{O}_{4}}=.2\times 50\times 5=50\] M eq. of \[{{H}_{2}}{{O}_{2}}=2\times 25\times .5=25\] M eq. of \[KMn{{O}_{4}}\]remaining = (50-25)=25 Mole of \[KMn{{O}_{4}}\]\[=\frac{25}{5}\times {{10}^{-3}}=5\times {{10}^{-3}}=.005\]
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