question_answer

50 mL of 0.1 M solution of a salt reacted with 25 mL of 0.1 M solution of sodium sulphite. The half reaction for the oxidation of sulphite ion is: \[S{{O}^{2-}}_{3}(aq)+{{H}_{2}}O(l)\to S{{O}^{2-}}_{4}(aq)=2{{H}^{+}}(aq)+2{{e}^{-}}\]if the oxidation number of metal in the slat was 3, what  would be the new oxidation number of metal?

Answer:

2