A) \[+\frac{7}{3}\]
B) \[-\frac{7}{3}\]
C) \[+\frac{5}{3}\]
D) \[-\frac{5}{3}\]
Correct Answer: A
Solution :
[a] \[(YB{{a}_{2}}C{{u}_{3}}{{O}_{7}})\] \[3+(2\times 2)+3x-14=0\] \[\therefore x=+\frac{7}{3}\]
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