A) \[\frac{{{10}^{-6}}}{4}\]
B) \[\frac{{{10}^{-4}}}{3}\]
C) \[3\times {{10}^{-5}}\]
D) \[{{10}^{-5}}\]
Correct Answer: B
Solution :
[b] \[\underset{+7}{\mathop{KMn{{O}_{4}}}}\,+3{{e}^{-}}\to \underset{+4}{\mathop{Mn{{O}_{2}}}}\,\] 5000 ml contains 0.01 eq. of \[Kmn{{O}_{4}}\] \[50ml\,\frac{0.01}{5000}\times 50\,eq.\,of\,KMn{{O}_{4}}\] Moles of \[Kmn{{O}_{4}}\]=\[\frac{Equivalents\,of\,KMn{{O}_{4}}}{V.F.}\] \[=\frac{0.01}{5000}\times \frac{50}{3}=\frac{{{10}^{-4}}}{3}\]
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