A) \[N{{H}_{3}}<{{N}_{2}}{{O}_{5}}<NO<{{N}_{2}}\]
B) \[N{{O}^{+}}_{2}<N{{O}^{-}}_{3}<N{{O}^{-}}_{2}<{{N}^{-}}_{3}\]
C) \[N{{H}^{+}}_{4}<{{N}_{2}}{{H}_{4}}<N{{H}_{2}}OH<{{N}_{2}}O\]
D) \[N{{O}_{3}}<Na{{N}_{3}}<N{{H}^{+}}_{4}<{{N}_{2}}O\]
Correct Answer: C
Solution :
[c] [a] \[\underset{-3}{\mathop{N{{H}_{3}}}}\,<\underset{+5}{\mathop{{{N}_{2}}{{O}_{5}}}}\,<\underset{+2}{\mathop{NO}}\,<\underset{0}{\mathop{{{N}_{2}}}}\,\](incorrect) [b] \[\underset{+5}{\mathop{N{{O}^{+}}_{2}}}\,<\underset{+5}{\mathop{N{{O}^{-}}_{3}}}\,<\underset{+3}{\mathop{N{{O}^{-}}_{2}}}\,<\underset{-1/3}{\mathop{{{N}^{-}}_{3}}}\,\](incorrect) [c] \[\underset{-3}{\mathop{N{{H}^{+}}_{4}}}\,<\underset{-2}{\mathop{{{N}_{2}}{{H}_{4}}}}\,<\underset{-1}{\mathop{N{{H}_{2}}OH}}\,<\underset{+1}{\mathop{{{N}_{2}}O}}\,\](incorrect) [d] \[\underset{+6}{\mathop{N{{O}_{3}}}}\,<\underset{-1/3}{\mathop{Na{{N}_{3}}}}\,<\underset{-3}{\mathop{N{{H}_{4}}^{+}}}\,<\underset{+1}{\mathop{{{N}_{2}}O}}\,\](incorrect)
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