A) 3
B) 3-n
C) n-3
D) +n
Correct Answer: B
Solution :
[b] Meq. of \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}=Meq.\]of ABD n-factor of \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}\]in acidic medium =6 \[6\times 1.68\times {{10}^{-3}}=x\times 3.26\times {{10}^{-3}}\] \[x=3\] \[\Rightarrow \]New oxidation state of \[{{A}^{-n}}\]will be =-n+3You need to login to perform this action.
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