A) 18/595
B) 6/17
C) 3/10
D) 2/7
Correct Answer: A
Solution :
[a] The ratios of the ships A, B, and C for arriving safely are 2:5, 3:7, and 6:11, respectively. Therefore, the probability of ship A for arriving safely is 2/(2+5)=2/7. Similarly, for B the probability is 3/(3+7)=3/10 and for C the probability is C=6/(6+11)=6/17. Therefore, the probability of all the ships for arriving safely is \[(2/4)\times (3/10)\times (6/17)=18/595.\]
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